16. 16. man pushes a 50 box up a 5.0-m long ramp. The box was 16. A man pushes a 500-N raised a vertical distance of 2.5 m. The actual work done by the worker was - 750J 1250 J 1500 J 2500J

Question

16. 16. man pushes a 50 box up a 5.0-m long ramp. The box was 16. A man pushes a 500-N raised a vertical distance of 2.5 m. The actual work done by the worker was - 750J 1250 J 1500 J 2500J

Answer 1

To calculate the actual work done by the worker, we need to consider both the work done against gravity and the work done against friction.1. Work done against gravity:The weight of the box is 500 N, and it is raised vertically by 2.5 m. The work done against gravity is given by:Work = Force x DistanceWork = 500 N x 2.5 m = 1250 J2. Work done against friction:The angle of the ramp can be calculated using the given information. The vertical distance is 2.5 m, and the length of the ramp is 5.0 m. Using trigonometry, we can find the angle:sin(θ) = Opposite / Hypotenusesin(θ) = 2.5 m / 5.0 mθ = sin^(-1)(0.5) = 30°The force of friction can be calculated using the coefficient of friction (μ) and the normal force. The normal force is equal to the weight of the box (500 N) times the cosine of the angle (30°):Normal Force = 500 N x cos(30°) = 500 N x √3/2 ≈ 433.01 NAssuming a coefficient of friction (μ) of 0.3, the force of friction is:Force of friction = μ x Normal ForceForce of friction = 0.3 x 433.01 N ≈ 129.9 NThe work done against friction is given by:Work = Force of friction x DistanceWork = 129.9 N x 5.0 m ≈ 649.5 J3. Total work done by the worker:The total work done by the worker is the sum of the work done against gravity and the work done against friction:Total Work = 1250 J + 649.5 J ≈ 1899.5 JTherefore, the actual work done by the worker is approximately 1900 J.

Problemas

16. 16. man pushes a 50 box up a 5.0-m long ramp. The box was 16. A man pushes a 500-N raised a vertical distance of 2.5 m. The actual work done by the worker was - 750J 1250 J 1500 J 2500J

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