Problemas
Read the passage and answer the following question(s) Passage 8728 Directions: The balanced equation shows the reaction of nontic acid and sodium hydroxide. 7.29 milliers (mL) of 0.87 M NoOH reacts completely with 1215 mL of CH_(3)COOH Use this information and the equation to answer any questions that follow. CH_(3)COOH+NaOHarrow HOH+NaCH_(3)COO What is the concentration of acetic acid, in terms of its molarity? 0.384 M 0.756 M 1.044 M 0.522 M
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To find the concentration of acetic acid, we need to use the balanced equation and the given information.Given:- Volume of NaOH: 7.29 mL- Molarity of NaOH: 0.87 M- Volume of CH3COOH: 1215 mLStep 1: Calculate the moles of NaOH.Moles of NaOH = Molarity × VolumeMoles of NaOH = 0.87 M × 0.00729 LMoles of NaOH = 0.00634 molStep 2: Use the balanced equation to find the moles of CH3COOH.From the balanced equation, we know that 1 mole of CH3COOH reacts with 1 mole of NaOH.Therefore, moles of CH3COOH = moles of NaOHMoles of CH3COOH = 0.00634 molStep 3: Calculate the concentration of acetic acid.Concentration of CH3COOH = Moles / VolumeConcentration of CH3COOH = 0.00634 mol / 0.1215 LConcentration of CH3COOH = 0.0522 MTherefore, the concentration of acetic acid is 0.0522 M.