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You Run an Experiment According to This Equation: 2HCl+CaCO_(3)arrow H_(2)O+CaCl_(2) +CO_(2) When Running Your Lab You Started with 62

Problemas

You run an experiment according to this equation: 2HCl+CaCO_(3)arrow H_(2)O+CaCl_(2) +CO_(2) When running your lab you started with 62 .16 grams of HCl and 50.18 grams of CaCO_(3) If, after the reaction finishes, your products have a total mass of 80.10, what was the percent yield? Round your answer to the nearest 0.01 and include units! Your Answer: square square Answer units

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Explicación

## Step1: Calculate the Molar Masses### Determine the molar masses of and using their atomic weights.- : - : ## Step2: Calculate Moles of Reactants### Convert the given masses of and to moles.- Moles of : - Moles of : ## Step3: Determine Limiting Reactant### Identify the limiting reactant by comparing the mole ratio from the balanced equation.- The balanced equation shows a 2:1 ratio of to .- Required moles of for 0.501 mol of : - Since we have 1.705 mol of , is the limiting reactant.## Step4: Calculate Theoretical Yield### Use the limiting reactant to calculate the theoretical yield of products.- Total mass of reactants: - Theoretical mass of products (should be equal to total mass of reactants): ## Step5: Calculate Percent Yield### Compare the actual mass of products to the theoretical mass to find the percent yield.- Actual mass of products: - Percent yield: