Given a gas is at 1 L and 291 K, what is the temperature of the gas when volume changes to 12 L? 3600 K 3000 K 3492 K 273 K

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. The formula for Charles's Law is:V1 / T1 = V2 / T2Where:V1 = Initial volumeT1 = Initial temperatureV2 = Final volumeT2 = Final temperatureGiven:V1 = 1 LT1 = 291 KV2 = 12 LWe need to find T2.Using the formula, we can rearrange it to solve for T2:T2 = (V2 * T1) / V1Plugging in the given values:T2 = (12 L * 291 K) / 1 LT2 = 3492 KTherefore, the temperature of the gas when the volume changes to 12 L is 3492 K.