20) through: (-1,-3) perp.to y=-(5)/(3)x-4 A) y=-(12)/(5)x+(3)/(5) B) y=-(3)/(5)x-(12)/(5) C) y=(2)/(5)x-(12)/(5) D) y=(3)/(5)x-(12)/(5)

To find the equation of the line that passes through the point and is perpendicular to the line , we need to determine the slope of the perpendicular line.The slope of the given line is . The slope of a line perpendicular to this line is the negative reciprocal of , which is .Now, we can use the point-slope form of a linear equation to find the equation of the perpendicular line. The point-slope form is given by: where is a point on the line and is the slope.Substituting the point and the slope into the point-slope form get: Simplifying this equation, we have: Therefore, the equation of the line that passes through the point and is perpendicular to the line is .The correct answer is D) .