Question 11 (1 point) A force 50N acts on a stationary object for 3 secs. If the mass of the object is 25 kg what is the change in velocity of the object? p=mv J=Ft=mDelta v m_(1)v_(1i)+m_(2)v_(2i)=m_(1)v_(1f)+m_(2)v_(2f) a 6m/s b 0.667m/s 3750m/s d 150m/s

Question

Question 11 (1 point) A force 50N acts on a stationary object for 3 secs. If the mass of the object is 25 kg what is the change in velocity of the object? p=mv J=Ft=mDelta v m_(1)v_(1i)+m_(2)v_(2i)=m_(1)v_(1f)+m_(2)v_(2f) a 6m/s b 0.667m/s 3750m/s d 150m/s

Answer 1

To solve this problem, we need to use the formula for impulse and momentum.Given information:- Force (F) = 50 N- Time (t) = 3 s- Mass (m) = 25 kgStep 1: Calculate the impulse (J) applied to the object.Impulse (J) = Force (F) × Time (t)J = 50 N × 3 s = 150 N·sStep 2: Use the impulse-momentum theorem to find the change in velocity (Δv).Impulse (J) = Change in momentum (Δp)J = m × Δv150 N·s = 25 kg × ΔvΔv = 150 N·s / 25 kg = 6 m/sTherefore, the change in velocity of the object is 6 m/s.The correct answer is a) 6 m/s.

Problemas

Question 11 (1 point) A force 50N acts on a stationary object for 3 secs. If the mass of the object is 25 kg what is the change in velocity of the object? p=mv J=Ft=mDelta v m_(1)v_(1i)+m_(2)v_(2i)=m_(1)v_(1f)+m_(2)v_(2f) a 6m/s b 0.667m/s 3750m/s d 150m/s

Roztwór

Respuesta