SUED SEE SAMPLE PROBLEM A painter mixes red paint with yellow paint to make orange paint. The painter has a total of 10 liters of paint.The red paint costs 5 per liter, and the yellow paint costs 4 per liter. If the total cost of the paint mixture is 47 how many liters of red paint and how many liters of yellow paint were used? Amount of paint: __ .......... Answer: __ .. litters of red paint and. __ __

To solve this problem, we need to set up a system of linear equations based on the given information.Let's define the variables:- Let x be the amount of red paint (in liters)- Let y be the amount of yellow paint (in liters)We are given the following information:1. The total amount of paint is 10 liters.2. The cost of red paint is 4 per liter.4. The total cost of the paint mixture is 47)Now, we can solve this system of equations to find the values of x and y.Step 1: Solve Equation 1 for y:y = 10 - xStep 2: Substitute the expression for y into Equation 2:5x + 4(10 - x) = 475x + 40 - 4x = 47x = 7Step 3: Substitute the value of x into Equation 1 to find y:7 + y = 10y = 3Therefore, the painter used 7 liters of red paint and 3 liters of yellow paint.