Ethane gas burns in air to form carbon dioxide and water. How many moles of carbon dioxide (CO_(2)) are produced for each 6.0 mole of water (H_(2)O) produced? 2C_(2)H_(6)+7O_(2)arrow 4CO_(2)+6H_(2)O 1 moles of CO_(2) 6 moles of CO_(2) 4 moles of CO_(2) 3 moles of CO_(2)

Question

Ethane gas burns in air to form carbon dioxide and water. How many moles of carbon dioxide (CO_(2)) are produced for each 6.0 mole of water (H_(2)O) produced? 2C_(2)H_(6)+7O_(2)arrow 4CO_(2)+6H_(2)O 1 moles of CO_(2) 6 moles of CO_(2) 4 moles of CO_(2) 3 moles of CO_(2)

Answer 1

To determine the number of moles of carbon dioxide (CO2) produced for each 6.0 moles of water (H2O) produced, we need to use the balanced chemical equation provided:2C2H6 + 7O2 → 4CO2 + 6H2OFrom the equation, we can see that for every 6 moles of water produced, 4 moles of carbon dioxide are produced.Therefore, the correct answer is:4 moles of CO2

Problemas

Ethane gas burns in air to form carbon dioxide and water. How many moles of carbon dioxide (CO_(2)) are produced for each 6.0 mole of water (H_(2)O) produced? 2C_(2)H_(6)+7O_(2)arrow 4CO_(2)+6H_(2)O 1 moles of CO_(2) 6 moles of CO_(2) 4 moles of CO_(2) 3 moles of CO_(2)

Roztwór

Respuesta