Problemas
Suppose that the functions g and h are defined as follows. g(x)=-5+4x^2 h(x)=4-9x (a) Find ((g)/(h))(3) (b) Find all values that are NOT in the domain of (g)/(h) If there is more than one value, separate them with commas. (a) ((g)/(h))(3)=square (b) Value(s) that are NOT in the domain of (g)/(h):square
Roztwór
David
maestro · Tutor durante 5 años
4.4
(207 Votos)
Respuesta
(a) To find
, we need to substitute
into both
and
and then divide the result of
by the result of
.First, let's find
:
Next, let's find
:
Now, we can find
:
Therefore,
.(b) The values that are NOT in the domain of
are the values for which
, since division by zero is undefined.To find these values, we set
and solve for
4 - 9x = 0
9x = 4
x = \frac{4}{9}
\frac {g}{h}
\frac{4}{9}
(\frac {g}{h})(3) = -\frac{31}{23}
\frac {g}{h}
\frac{4}{9}$