The maximum height H of an object launched with initial velocity v_(0) at an angle Theta is given by the following formula. H=(v_(0)^2sin^2Theta )/(2g) If g=9.8m/s^2 , find the height of an object when v_(0)=90m/s and Theta =1.83 rad. Do not round any intermediate computations. Round your answer to the nearest hundredth. H=square m

Question

Answer 1

To find the height

of the object, we will use the given formula:

Given:-

-

First, we need to calculate

:

Using a calculator:

So,

Now, substitute the values into the formula:

Calculate the numerator:

Now, divide by the denominator:

Therefore, the height

of the object is approximately:

So, the the object is:

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