Problemas
2KClO_(3)arrow 2KCl+3O_(2) If there are 6.73times 10^23 particles of KClO_(3) find the number of grams of O_(2) that are produced. (mmO_(2)=32g/mol)(mmKClO_(3)=122g/mol) 53.668 107.32 g 82.73 g 42.10 g
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Cristina
élite · Tutor durante 8 años
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Respuesta
To solve this problem, we need to follow these steps:1. Calculate the number of moles of KClO3 using Avogadro's number.2. Use the stoichiometry of the balanced chemical equation to find the number of moles of O2 produced.3. Convert the number of moles of O2 to grams using the molar mass of O2.Given information:- Balanced chemical equation: 2KClO3 → 2KCl + 3O2- Number of particles of KClO3: 6.73 × 10^23- Molar mass of O2: 32 g/mol- Molar mass of KClO3: 122 g/molStep 1: Calculate the number of moles of KClO3.Number of moles of KClO3 = Number of particles / Avogadro's numberNumber of moles of KClO3 = 6.73 × 10^23 / 6.022 × 10^23Number of moles of KClO3 = 1.12 molesStep 2: Use the stoichiometry of the balanced chemical equation to find the number of moles of O2 produced.According to the balanced chemical equation, 2 moles of KClO3 produce 3 moles of O2.Number of moles of O2 produced = (3/2) × Number of moles of KClO3Number of moles of O2 produced = (3/2) × 1.12 molesNumber of moles of O2 produced = 1.68 molesStep 3: Convert the number of moles of O2 to grams using the molar mass of O2.Mass of O2 = Number of moles of O2 × Molar mass of O2Mass of O2 = 1.68 moles × 32 g/molMass of O2 = 53.76 gTherefore, the correct answer is 53.76 g.