Problemas
5) Calculate the mass of silver phosphate produced from 36.2g of silver acetate if sodium phosphate and silver acetate produce silver phosphate and sodium acetate in the reaction Na_(3)PO_(4)+3AgC_(2)H_(3)O_(2)arrow Ag_(3)PO_(4)+3NaC_(2)H_(3)O_(2)
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Alejandra
professionell · Tutor durante 6 años
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To calculate the mass of silver phosphate produced from 36.2g of silver acetate, we need to follow these steps:1. Determine the molar mass of silver acetate (AgC2H3O2) and silver phosphate (Ag3PO4).2. Convert the mass of silver acetate to moles using its molar mass.3. Use the stoichiometry of the balanced chemical equation to find the moles of silver phosphate produced.4. Convert the moles of silver phosphate to grams using its molar mass.Let's go through these steps:1. Molar masses: - Silver acetate (AgC2H3O2): 166.97 g/mol (Ag) + 2(12.01 g/mol) + 3(1.01 g/mol) + 2(16.00 g/mol) = 166.97 g/mol - Silver phosphate (Ag3PO4): 3(166.97 g/mol) + 30.97 g/mol (P) + 4(16.00 g/mol) = 418.58 g/mol2. Convert the mass of silver acetate to moles: Moles of silver acetate = 36.2 g / 166.97 g/mol = 0.216 mol3. Use the stoichiometry of the balanced chemical equation: According to the balanced equation, 3 moles of silver acetate produce 1 mole of silver phosphate. Moles of silver phosphate = 0.216 mol AgC2H3O2 * (1 mol Ag3PO4 / 3 mol AgC2H3O2) = 0.072 mol Ag3PO44. Convert the moles of silver phosphate to grams: Mass of silver phosphate = 0.072 mol * 418.58 g/mol = 30.0 gTherefore, the mass of silver phosphate produced from 36.2g of silver acetate is 30.0 grams.