Question 1 of 25 How many degrees will 340 J raise the temperature of 6.8 g of water? (Refer to table of constants for water.) A. 28^circ C B. 50^circ C C. 81^circ C D. 12^circ C

To solve this problem, we need to use the formula for calculating the change in temperature of a substance when a certain amount of heat energy is added or removed. The formula is:ΔT = Q / (m × c)Where:- ΔT is the change in temperature (in degrees Celsius)- Q is the amount of heat energy added or removed (in joules)- m is the mass of the substance (in grams)- c is the specific heat capacity of the substance (in joules per gram per degree Celsius)Given information:- Q = 340 J- m = 6.8 g- c = 4.18 J/g°C (specific heat capacity of water)Plugging in the values, we get:ΔT = 340 J / (6.8 g × 4.18 J/g°C)ΔT = 340 J / 28.424 J/°CΔT = 11.94°CTherefore, the correct answer is:D.