6. How many grams of barium chloride are produced when 1.25times 10^23 molecules of HCl reacts with barium according to the following equation? Word equation: hydrochloric acid+bariumarrow barium hydroxide+hydrogen Formula equation: 2HCl+1Baarrow 1BaCl_(2)+1H_(2)

To solve this problem, we need to follow these steps:1. Convert the given number of molecules of HCl to moles.2. Use the stoichiometry of the balanced chemical equation to determine the moles of BaCl2 produced.3. Convert the moles of BaCl2 to grams.Step 1: Convert the given number of molecules of HCl to moles.Given: molecules of HClMoles of HCl = = 2.07 molesStep 2: Use the stoichiometry of the balanced chemical equation to determine the moles of BaCl2 produced.According to the balanced chemical equation, 2 moles of HCl produce 1 mole of BaCl2.Moles of BaCl2 produced = = 1.035 molesStep 3: Convert the moles of BaCl2 to grams.Molar mass of BaCl2 = 208.23 g/molMass of BaCl2 produced = 1.035 moles × 208.23 g/mol = 214.6 gramsTherefore, 214.6 grams of barium chloride are produced when molecules of HCl react with barium according to the given equation.