D. 2. What is the molar mass of Ca_(3)(PO_(4))_(2) Din) 3108 Din) 3428 Do 2798 2468

The molar mass of is 3108 g/mol.Explanation:The molar mass of a compound is the sum of the molar masses of its constituent atoms. In this case, the compound is , which consists of 3 calcium atoms (Ca), 2 phosphate groups (PO4).The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. The molar mass of phosphorus (P) is approximately 30.97 g/mol.To calculate the molar mass of , we need to multiply the molar mass of each atom by the number of times it appears in the compound and then add them together.Molar mass of = (3 × 40.08 g/mol) + (2 × (30.97 g/mol + 4 × 16.00 g/mol))= 120.24 g/mol + 2 × (30.97 g/mol + 64.00 g/mol)= 120.24 g/mol + 2 × 94.97 g/mol= 120.24 g/mol + 189.94 g/mol= 310.18 g/molTherefore, the molar mass of is 3108 g/mol.