Problemas
A form of technetium -99 has a half-life of approximately 6 hours (}_{43)^99TCarrow underline ( )+_(-1)^0e+gamma Which substance correctly completes the equation above? A (}_{42)^99Mo B (}_{43)^94Te C (}_{43)^99Es D (}_{44)^99Ru
Roztwór
Rubén
professionell · Tutor durante 6 años
4.3
(73 Votos)
Respuesta
A
Explicación
## Step 1The problem involves a nuclear decay process, specifically beta decay. In beta decay, a neutron in the nucleus of an atom is converted into a proton, an electron (also known as a beta particle), and an antineutrino. The atomic number increases by one, but the atomic mass number remains the same.## Step 2In this case, the parent atom is Technetium-99 (Tc), which has an atomic number of 43. The atomic mass number remains the same, so the atomic number of the daughter atom must be 44.## Step 3Looking at the options, only option A, Molybdenum-99 (Mo), has an atomic number of 44. Therefore, it is the correct answer.