A Question 1 (1 point) Retake question Methane burns according to the equation CH_(4)+O_(2)... CO_(2)+H_(2)O You burn 1.77 grams of methane (CH_(4)) in excess oxygen and collect 1.79 grams of water. What is the percent yield for this reaction to the nearest 0.01 ? Your Answer: square square

Question

Answer 1

### 45.04%

Answer 2

## Step1: Write the Balanced Chemical Equation### The balanced chemical equation for the combustion of methane is

. This shows that one mole of methane produces two moles of water.## Step2: Calculate Moles of Methane Burned### The molar mass of methane (

) is

. Therefore, the moles of methane burned are

.## Step3: Calculate Theoretical Yield of Water### According to the balanced equation, 1 mole of

produces 2 moles of

. Thus,

of

will produce

of

. The molar mass of water is

, so the theoretical yield is

.## Step4: Calculate Percent Yield### The percent yield is calculated using the formula

. Substituting the values gives

.

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