4. (NH_(4))_(3)PO_(4)=underline ( )g % N=underline ( ) % H=underline ( ) % P=underline ( ) % O=underline ( )

To find the percentage composition of each element in , we need to calculate the molar mass of the compound and then determine the mass of each element as a percentage of the total molar mass.The molar mass of is calculated as follows:- Nitrogen (N): 14.01 g/mol × 3 = 42.03 g/mol- Hydrogen (H): 1.01 g/mol × 12 = 12.12 g/mol- Phosphorus (P): 30.97 g/mol × 1 = 30.97 g/mol- Oxygen (O): 16.00 g/mol × 4 = 64.00 g/molTotal molar mass = 42.03 + 12.12 + 30.97 + 64.00 = 149.12 g/molNow, we can calculate the percentage composition of each element:- Nitrogen (N): (42.03 g/mol / 149.12 g/mol) × 100% = 28.21%- Hydrogen (H): (12.12 g/mol / 149.12 g/mol) × 100% = 8.15%- Phosphorus (P): (30.97 g/mol / 149.12 g/mol) × 100% = 20.88%- Oxygen (O): (64.00 g/mol / 149.12 g/mol) × 100% = 42.86%Therefore, the percentage composition of each element in is as follows:- Nitrogen (N): 28.21%- Hydrogen (H): 8.15%- Phosphorus (P): 20.88%- Oxygen (O): 42.86%