a=(1)/(n)times 10.95,Mole5=5.465,Mults at STP in order to produce potassium nitride according to the following reaction? 6K+N_(2)arrow 2K_(3)N

To determine the number of moles of potassium (K) needed to produce potassium nitride (K3N) at standard temperature and pressure (STP), we need to use the balanced chemical equation provided: First, let's find the molar ratio between potassium (K) and potassium nitride (K3N). According to the balanced equation, 6 moles of potassium (K) are required to produce 2 moles of potassium nitride (K3N).Next, we need to calculate the number of moles of potassium (K) using the given molar mass of potassium (K) and the given mass of potassium (K): Given:- Molar mass of potassium (K) = 39.10 g/mol- Mass of potassium (K) = 10.95 gFirst, calculate the number of moles of potassium (K): Now, use the molar ratio to find the number of moles of potassium nitride (K3N) produced: Therefore, 0.047 moles of potassium nitride (K3N) will be produced when 0.28 moles of potassium (K) react with nitrogen (N2) at STP.