Problemas
Simplify. Enter the result as a single logarithm with a coefficient of 1 log_(5)(7x^3)+log_(5)(8x^4)=square
Roztwór
Gilda
professionell · Tutor durante 6 años
4
(292 Votos)
Respuesta
The final answer is \(log_{5}(56x^{7})\).
Explicación
## Step 1We are given two logarithms with the same base, which are \(log_{5}(7x^{3})\) and \(log_{5}(8x^{4})\). According to the properties of logarithms, we can combine these two logarithms into one by using the product rule of logarithms.### **The product rule of logarithms: \(log_{b}(M) + log_{b}(N) = log_{b}(MN)\)**## Step 2Applying the product rule to our given problem, we get:### **\(log_{5}(7x^{3}) + log_{5}(8x^{4}) = log_{5}(7x^{3} * 8x^{4})\)**## Step 3Next, we simplify the expression inside the logarithm by multiplying the coefficients and adding the exponents of the variables.### **\(log_{5}(7x^{3} * 8x^{4}) = log_{5}(56x^{7})\)**## Step 4Finally, we simplify the expression inside the logarithm by multiplying the coefficients and adding the exponents of the variables.### **\(log_{5}(56x^{7}) = log_{5}(56x^{7})\)**