Problemas
PoS3+6FrBrarrow PoBr6+3Fr2S How many grams of Fr2S do I get from 252.3 grams of PoS3? (Po=209S=32Fr=223) 478 g 395 g 1434 g 1185 g
Roztwór
Elisa
professionell · Tutor durante 6 años
4.7
(313 Votos)
Respuesta
To solve this problem, we need to use the concept of stoichiometry and the given molar masses of the compounds involved.Given information:- The balanced chemical equation is:
- The molar masses are:
,
,
Step 1: Calculate the molar mass of
.Molar mass of
g/molStep 2: Calculate the molar mass of
.Molar mass of
g/molStep 3: Calculate the number of moles of
.Number of moles of
Step 4: Use the stoichiometry of the balanced equation to find the number of moles of
.According to the balanced equation, 1 mole of
produces 3 moles of
.Number of moles of
Step 5: Calculate the mass of
.Mass of
Therefore, the correct answer is 1008.732 g.