You have 0.5 Lof air at 203 K in an expandable container at constant pressure. You heat the container to 273 K. What is the volume of air? (V_(1))/(T_(1))=(V_(2))/(T_(2)) T_(1)=203K V_(2)=? T_(2)=273K

To solve this problem, we can use the ideal gas law equation: Given: We need to find .Substituting the given values into the equation: Cross-multiplying: Solving for : Therefore, the volume of air in the container when heated to 273K is approximately 0.674L.