Problemas
How long does it take a 2000-Kg car to stop from a velocity of 35m/s if a braking force of 4000 Newtons is used? p=mv m_(1)v_(1f)+m_(2)v_(2i)=m_(f)v_(1f)+m_(2)v_(2f) 10 seconds b 17.5 seconds 70 seconds d B.75 seconds Question 23 (1 point) Sug
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Adolfo
professionell · Tutor durante 6 años
4.3
(259 Votos)
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To solve this problem, we need to use the principles of physics, specifically the concepts of momentum and Newton's second law.Given information:- Mass of the car (m) = 2000 kg- Initial velocity (v) = 35 m/s- Braking force (F) = 4000 NStep 1: Calculate the acceleration (a) using Newton's second law.Newton's second law states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.F = m × aa = F / ma = 4000 N / 2000 kga = 2 m/s²Step 2: Calculate the time (t) it takes for the car to stop.The car's initial momentum is given by p_initial = m × v.The car's final momentum is 0 (since the car comes to a stop).Using the conservation of momentum:p_initial = p_finalm × v = 0t = v / at = 35 m/s / 2 m/s²t = 17.5 secondsTherefore, the correct answer is:b) 17.5 seconds