Problemas
Consider the following code segment, which is intended to store ten consecutive even integers, beginning with 2, in the list evenlist. Assume that evenList is initially empty. iarrow 1 REPEAT 10 TIMES MISSING CODE> Which of the following can be used to replace <MISSING CODE> SO that the code segment works as intended? A APPEND(evenList, 1) iarrow i+2 B iarrow i+2 APPEND(evenList, i) C (c) APPEND(even List, 2ast i iarrow i+1 D iarrow i+1 APPEN ocev enLi st, 2ast i
Roztwór
Fernando
élite · Tutor durante 8 años
4.4
(208 Votos)
Respuesta
To solve this problem, we need to understand the requirements of the code segment and the options provided.The code segment is intended to store ten consecutive even integers, starting with 2, in the list evenList. The initial value of i is 1, and the code segment is repeated 10 times.Let's analyze the options:A. APPEND(evenList, 1) i <- i + 2 This option appends the number 1 to the list, which is not an even integer. Therefore, this option is incorrect.B. i <- i + 2 APPEND(evenList, i) This option increments the value of i by 2 and then appends the value of i to the list. However, this will not produce the correct sequence of even integers. Therefore, this option is incorrect.C. APPEND(evenList, 2*i) i <- i + 1 This option appends the value of 2*i to the list and then increments the value of i by 1. This will produce the correct sequence of even integers. Therefore, this option is correct.D. i <- i + 1 APPEND(evenList, 2*i) This option increments the value of i by 1 and then appends the value of 2*i to the list. This will also produce the correct sequence of even integers. Therefore, this option is correct.Therefore, the correct answer is option C.