Consider the following balanced chemical equation: 2Fe(s)+3Pb(NO_(3))_(2)(aq)arrow 3Pb(s)+2Fe(NO_(3)) If 3.6 moles of Fe are reacted, how many moles of Pb(NO_(3))_(2) were reacted? square

To determine how many moles of \( Pb(NO_3)_2 \) were reacted when 3.6 moles of Fe are reacted, we need to use the stoichiometric relationship from the balanced chemical equation: From the equation, we see that 2 moles of Fe react with 3 moles of \( Pb(NO_3)_2 \).We can set up a proportion to find the number of moles of \( Pb(NO_3)_2 \) that react with 3.6 moles of Fe: Now, solve for : Therefore, 5.4 moles of \( Pb(NO_3)_2 \) were reacted.