A 41.0 mL barium hydroxide solution of molarity 3.41M is diluted with water to form 279 mL of the solution. Calculate the molarity of the solution.

To calculate the molarity of the solution after dilution, we can use the formula:M1V1 = M2V2:M1 = initial molarityV1 = initial volumeM2 = final molarityV2 = final volumeGiven information:- Initial molarity (M1) = 3.41 M- Initial volume (V1) = 41.0 mL- Final volume (V2) = 279 mLSubstituting the values in the formula:M1V1 = M2V2(3.41 M)(41.0 mL) = M2(279 mL)M2 = (3.41 M)(41.0 mL) / (279 mL)M2 = 0.505 MTherefore, the molarity of the solution after dilution is 0.505 M.