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2. H(x)=x^2-4x-5 X-intercept(s): __ Y-intercept: __ Axis of Symmetry: __ Vertex: __ Max or Min Domain: __ Range: __

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2. h(x)=x^2-4x-5 X-intercept(s): __ Y-intercept: __ Axis of Symmetry: __ Vertex: __ Max or Min Domain: __ Range: __

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Ricardo élite · Tutor durante 8 años
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Respuesta

X-intercept(s): 5, -1Y-intercept: -5Axis of Symmetry: x=2Vertex: (2, -9) MaxDomain: (-∞, ∞)Range: (-∞, -9]

Explicación

## Step 1:The x-intercepts of a function are the values of x for which the function equals zero. In this case, we need to solve the equation .## Step 2:The y-intercept of a function is the value of the function when x equals zero. In this case, we need to evaluate \(h(0)\).## Step 3:The axis of symmetry of a parabola is the vertical line that passes through the vertex of the parabola. For a quadratic function in the form \(f(x)=ax^{2}+bx+c\), the axis of symmetry is given by the formula .## Step 4:The vertex of a parabola is the point where the parabola reaches its maximum or minimum value. For a quadratic function in the form \(f(x)=ax^{2}+bx+c\), the vertex is given by the point \((-b/2a, f(-b/2a))\).## Step 5:The domain of a function is the set of all possible x-values. For a quadratic function, the domain is all real numbers.## Step 6:The range of a function is the set of all possible y-values. For a quadratic function that opens upwards, the range is all y-values greater than or equal to the y-coordinate of the vertex.