BONUS +10 POINTS) Using the given moles from #3 for MnO_(2) and HCl, calculate how many be produced. 0.86 mol of MnO_(2) produces __ grams of Cl_(2) 4.82 mol of HCl produces __ grams of Cl_(2)

## Step 1: First, we need to understand the chemical reaction involved. The reaction between manganese dioxide (MnO2) and hydrochloric acid (HCl) can be represented as follows:### From the balanced chemical equation, we can see that 1 mole of MnO2 reacts with 4 moles of HCl to produce 1 mole of Cl2.## Step 2:Now, let's calculate the amount of Cl2 produced from 0.86 moles of MnO2.Since 1 mole of MnO2 produces 1 mole of Cl2, 0.86 moles of MnO2 will produce 0.86 moles of Cl2.## Step 3:Next, we need to convert the moles of Cl2 to grams. The molar mass of Cl2 is approximately 70.9 g/mol.So, the mass of Cl2 produced from 0.86 moles of MnO2 is grams.## Step 4:Now, let's calculate the amount of Cl2 produced from 4.82 moles of HCl.Since 4 moles of HCl produce 1 mole of Cl2, 4.82 moles of HCl will produce moles of Cl2.## Step 5:Finally, we convert the moles of Cl2 to grams using the molar mass of Cl2.So, the mass of Cl2 produced from 4.82 moles of HCl is grams.