Item 2 Item 1 Which of the following statements is TRUE regarding cable splices in cable trays? a) Splices must be insulated using NEC^8 approved methods. b) Splices must be installed where they are inaccessible. c) Splices are never permitted in cable tray. d) Splices should be left unsecured to allow for expansion and contraction. Confidence Level: Confident Unsure Guessed Scoring Scale: 012 3 4 Given a cable tray that is available in standard widths of 6,12,18,24, and 36 inches, what is the minimum width of a 3-inch-deep cable tray used for the following cables that are all 4/0 or larger: two 1.75-inch diameter cables and four 2.5-inch diameter cables? a) 12 inches b) 18 inches c) 24 inches d) 36 inches Confidence Level: Confident Unsure Guessed It It

Question

Item 2 Item 1 Which of the following statements is TRUE regarding cable splices in cable trays? a) Splices must be insulated using NEC^8 approved methods. b) Splices must be installed where they are inaccessible. c) Splices are never permitted in cable tray. d) Splices should be left unsecured to allow for expansion and contraction. Confidence Level: Confident Unsure Guessed Scoring Scale: 012 3 4 Given a cable tray that is available in standard widths of 6,12,18,24, and 36 inches, what is the minimum width of a 3-inch-deep cable tray used for the following cables that are all 4/0 or larger: two 1.75-inch diameter cables and four 2.5-inch diameter cables? a) 12 inches b) 18 inches c) 24 inches d) 36 inches Confidence Level: Confident Unsure Guessed It It

Answer 1

For the first question, the correct answer is:a) Splices must be insulated using NEC approved methods.Explanation: According to the National Electrical Code (NEC), splices in cable trays must be insulated using approved methods to ensure safety and prevent accidental contact with live wires.For the second question, the correct answer is:c) 24 inchesExplanation: To determine the minimum width of a 3-inch-deep cable tray for the given cables, we need to consider the diameter of the cables and the number of cables. In this case, we have two 1.75-inch diameter cables and four 2.5-inch diameter cables. The total width required for these cables is 1.75 inches + 1.75 inches + 2.5 inches + 2.5 inches = 8.5 inches. Therefore, the minimum width of the cable tray should be 24 inches to accommodate the cables properly.

Problemas

Roztwór

Respuesta