The number of grams of a radioactive isotope present after t years is 1,500((1)/(2))^t What does 1,500 represent in this situation if tgt 0 A. the original number of grams of the radioactive isotope present B. the number of grams of the radioactive isotope present after (1)/(2) year C. the number of grams of the radioactive isotope present after 2 years D. the final number of grams of the radioactive isotope present

The given function is . In this function, the number 1,500 is the initial amount of the radioactive isotope present before any decay has occurred. This is because when , the function simplifies to . This means that when , there are 1,500 grams of the radioactive isotope present. So, the number 1,500 in this situation represents the original number of grams of the radioactive isotope present. Therefore, the correct answer is A. the original number of grams of the radioactive isotope present.