If you want to throw a ball up 60 meters into the air, how fast must you initially throw it? 34.29m/s 58.29m/s 78.29m/s 98.29m/s

To solve this problem, we can use the kinematic equation for an object in free fall:v^2 = u^2 + 2asWhere:v = final velocity (0 m/s, since the ball reaches the maximum height)u = initial velocity (unknown)a = acceleration due to gravity (-9.8 m/s^2, negative since it acts downward)s = displacement (60 m, upward)Plugging in the values, we get:0 = u^2 + 2(-9.8)(60)0 = u^2 - 1176u^2 = 1176u = √1176u ≈ 34.29 m/sTherefore, the correct answer is .