Methane burns according to the equation CH_(4)+O_(2)... CO_(2)+H_(2)O You burn 1.77 grams of methane (CH_(4)) in excess oxygen and collect 1.79 grams of water. What is the percent yield for this reaction to the nearest 0.01 ? Your Answer: square square Answer units

Question

Answer 1

### 45.04%

Answer 2

## Step1: Write the balanced chemical equation### The balanced chemical equation for the combustion of methane is:

## Step2: Calculate moles of methane burned### Molar mass of

is

g/mol. Moles of

burned:

## Step3: Determine theoretical yield of water### According to the balanced equation, 1 mole of

produces 2 moles of

. Therefore, moles of

produced:

### Molar mass of

is

g/mol. Theoretical yield of

:

## Step4: Calculate percent yield### Percent yield is given by:

### Substituting the values:

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