Given a gas is at 21 Land 9 mol, what is the volume of the gas when the number of moles changes to 8 mol? Round to one decimal place. square

To solve this problem, we can use the ideal gas law equation:PV = nRTWhere:- P is the pressure of the gas- V is the volume of the gas- n is the number of moles of the gas- R is the universal gas constant- T is the absolute temperature of the gas- Initial number of moles (n1) = 21 L- Final number of moles (n2) = 8 molWe need to find the final volume (V2) of the gas when the number of moles changes to 8 mol.Using the ideal gas law equation, we can write:P1V1 = n1RTP2V2 = n2RTSince the pressure and temperature remain constant, we can equate the two equations:P1V1 = P2V2Substituting the given values:P1 × 21 L = P2 × V2To find the final volume (V2), we can rearrange the equation:V2 = (P1 × 21 L) / P2Since the pressure (P1 and P2) is the same, we can simplify the equation:V2 = 21 L × n2)Substituting the given values:V2 = 21 L × (21 L / 8 L)V2 = 56.25 LRounding the answer to one decimal place, the final volume of the gas when the number of moles changes to 8 mol is 56.3 L.