2H_(2)+O_(2)arrow 2H_(2)O How many moles of water would be produced from the reaction of 8.10 moles of hydrogen gas reacting with oxygen gas? 2.10 moles 4.05 moles 8.10 moles 16.2 moles

## Step1: Identify the Stoichiometric Ratio<br />### The balanced chemical equation is $2H_{2} + O_{2} \rightarrow 2H_{2}O$. This indicates that 2 moles of $H_{2}$ produce 2 moles of $H_{2}O$.<br />## Step2: Calculate Moles of Water Produced<br />### Given 8.10 moles of $H_{2}$, we use the stoichiometric ratio from the balanced equation to find the moles of $H_{2}O$ produced. Since the ratio is 1:1 (2 moles of $H_{2}$ produce 2 moles of $H_{2}O$), 8.10 moles of $H_{2}$ will produce 8.10 moles of $H_{2}O$.