A balloon has a volume of 2.5 L at a temperature of 300 K. If the temperature is increased to 450 K.what will be the new volume of the balloon?Assume pressure remains constant.

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to its temperature, provided that the pressure and the amount of gas remain constant. This relationship is known as Charles's Law.<br /><br />Mathematically, Charles's Law can be expressed as:<br /><br />V1/T1 = V2/T2<br /><br />Where:<br />V1 is the initial volume of the gas<br />T1 is the initial temperature of the gas<br />V2 is the final volume of the gas<br />T2 is the final temperature of the gas<br /><br />Given information:<br />- Initial volume (V1) = 2.5 L<br />- Initial temperature (T1) = 300 K<br />- Final temperature (T2) = 450 K<br /><br />We need to find the final volume (V2).<br /><br />Substituting the given values into the equation:<br /><br />V1/T1 = V2/T2<br />2.5 L / 300 K = V2 / 450 K<br /><br />Solving for V2:<br /><br />V2 = (2.5 L / 300 K) × 450 K<br />V2 = 3.75 L<br /><br />Therefore, the new volume of the balloon when the temperature is increased to 450 K, assuming pressure remains constant, will be 3.75 L.