Given a gas is at 21 Land 9 mol, what is the volume of the gas when the number of moles changes to 8 mol? Round to one decimal place. square L

## Step 1<br />The problem involves the application of Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of the gas, provided the temperature and pressure remain constant. This relationship can be expressed mathematically as:<br />### \(V1/n1 = V2/n2\)<br />where \(V1\) and \(n1\) represent the initial volume and number of moles, and \(V2\) and \(n2\) represent the final volume and number of moles.<br /><br />## Step 2<br />In this problem, we are given that the initial volume \(V1\) is 21 L and the initial number of moles \(n1\) is 9 mol. The number of moles changes to 8 mol, so \(n2 = 8\). We are asked to find the final volume \(V2\).<br /><br />## Step 3<br />We can rearrange the formula to solve for \(V2\):<br />### \(V2 = V1 * (n2/n1)\)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \(V2 = 21 * (8/9)\)<br /><br />## Step 5<br />Calculate the value of \(V2\).