Given a gas is at 25 L and 6 mol, what is the number of moles of the gas when volume changes to 20 L ? Round to one decimal place. square mol

## Step 1<br />The problem involves the application of Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of the gas, provided the temperature and pressure remain constant. This relationship can be represented by the formula:<br />### \(V1/n1 = V2/n2\)<br />where \(V1\) and \(n1\) are the initial volume and number of moles, and \(V2\) and \(n2\) are the final volume and number of moles.<br /><br />## Step 2<br />In this problem, we are given that the initial volume \(V1\) is 25 L, the initial number of moles \(n1\) is 6 mol, and the final volume \(V2\) is 20 L. We are asked to find the final number of moles \(n2\).<br /><br />## Step 3<br />We can rearrange the formula to solve for \(n2\):<br />### \(n2 = (V2 * n1) / V1\)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \(n2 = (20 * 6) / 25 = 4.8\)