Given a gas is at 22 L and 1 mol, what is the volume of the gas when the number of moles changes to 4 mol? Round to one decimal place. square L

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas, given that the temperature and pressure remain constant.<br /><br />The ideal gas law can be expressed as:<br /><br />V1/n1 = V2/n2<br /><br />where V1 is the initial volume, n1 is the initial number of moles, V2 is the final volume, and n2 is the final number of moles.<br /><br />Given that the initial volume is 22 L and the initial number of moles is 1 mol, we can substitute these values into the equation:<br /><br />V1/n1 = V2/n2<br />22 L/1 mol = V2/4 mol<br /><br />Solving for V2, we get:<br /><br />V2 = (22 L/1 mol) * 4 mol<br />V2 = 88 L<br /><br />Therefore, the volume of the gas when the number of moles changes to 4 mol is 88 L.