2 Formula 1 point underline ( )N_(2)+underline ( )H_(2)arrow underline ( )NH_(3) Nitrogen and hydrogen gas react together to form 225.0 L of ammonia (NH_(3)) How many liters of hydrogen gas is used up in this reaction? square

To solve this problem, we need to use the balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia.<br /><br />The balanced chemical equation is:<br />$N_{2} + 3H_{2} \rightarrow 2NH_{3}$<br /><br />Given information:<br />- The reaction produces 225.0 L of ammonia (NH3).<br /><br />To find the volume of hydrogen gas (H2) used up in the reaction, we can use the stoichiometric relationship between the reactants and the product.<br /><br />According to the balanced equation, for every 1 mole of nitrogen (N2) and 3 moles of hydrogen (H2) that react, 2 moles of ammonia (NH3) are produced.<br /><br />Since the volume of a gas is directly proportional to the number of moles, we can use the following relationship:<br />Volume of hydrogen gas (H2) = (3/2) × Volume of ammonia (NH3)<br /><br />Substituting the given value:<br />Volume of hydrogen gas (H2) = (3/2) × 225.0 L<br />Volume of hydrogen gas (H2) = 337.5 L<br /><br />Therefore, the volume of hydrogen gas used up in this reaction is 337.5 L.