1. KMnO_(4)=underline ( )g % K=underline ( ) % Mn=underline ( ) % O=underline ( )

To determine the percentage composition of each element in potassium permanganate (KMnO₄), we need to calculate the molar mass of KMnO₄ and then find the mass percentage of each element.<br /><br />1. **Calculate the molar mass of KMnO₄:**<br /> - Potassium (K): 39.10 g/mol<br /> - Manganese (Mn): 54.94 g/mol<br /> - Oxygen (O): 16.00 g/mol<br /><br /> The molar mass of KMnO₄ is:<br /> \[<br /> \text{Molar mass of KMnO₄} = 39.10 + 54.94 + (4 \times 16.00) = 158.04 \text{ g/mol}<br /> \]<br /><br />2. **Calculate the percentage composition of each element:**<br /><br /> - **Potassium (K):**<br /> \[<br /> \% \text{K} = \left( \frac{39.10}{158.04} \right) \times 100 \approx 24.74\%<br /> \]<br /><br /> - **Manganese (Mn):**<br /> \[<br /> \% \text{Mn} = \left( \frac{54.94}{158.04} \right) \times 100 \approx 34.76\%<br /> \]<br /><br /> - **Oxygen (O):**<br /> \[<br /> \% \text{O} = \left( \frac{64.00}{158.04} \right) \times 100 \approx 40.50\%<br /> \]<br /><br />So, the percentage composition of each element in KMnO₄ is:<br />- Potassium (K): 24.74%<br />- Manganese (Mn): 34.76%<br />- Oxygen (O): 40.50%