Multiply. (11p+3)(11p-3) a 121p^2-66p-9 b p^2-9 C 121p^2-9 d 121p^2+66p-9

To multiply the given expression \((11p+3)(11p-3)\), we can use the difference of squares formula, which states that \((a+b)(a-b) = a^2 - b^2\).<br /><br />In this case, \(a = 11p\) and \(b = 3\). Applying the formula, we get:<br /><br />\[<br />(11p+3)(11p-3) = (11p)^2 - 3^2<br />\]<br /><br />Now, calculate each term:<br /><br />\[<br />(11p)^2 = 121p^2<br />\]<br />\[<br />3^2 = 9<br />\]<br /><br />So, the expression simplifies to:<br /><br />\[<br />121p^2 - 9<br />\]<br /><br />Therefore, the correct answer is:<br /><br />c) \(121p^2 - 9\)