Find tan(330^circ ) -sqrt (3) sqrt (3) -(1)/(sqrt (2))

To find $\tan(330^{\circ})$, we can use the fact that $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$.<br /><br />First, let's find the reference angle for $330^{\circ}$. Since $330^{\circ}$ is in the fourth quadrant, the reference angle is $360^{\circ} - 330^{\circ} = 30^{\circ}$.<br /><br />Now, we know that $\tan(30^{\circ}) = \frac{1}{\sqrt{3}}$.<br /><br />Since $330^{\circ}$ is in the fourth quadrant, where tangent is negative, we have:<br /><br />$\tan(330^{\circ}) = -\tan(30^{\circ}) = -\frac{1}{\sqrt{3}}$<br /><br />Therefore, the correct answer is $-\frac{1}{\sqrt{3}}$.