x+y =12 y =x^2 o / If (x,y) is a solution to the given system of equations, which of the following is a possible value of x? A square B 1 C 2 D square

To solve the system of equations, we can substitute the value of y from the second equation into the first equation:<br /><br />$x + x^2 = 12$<br /><br />Rearranging the equation, we get:<br /><br />$x^2 + x - 12 = 0$<br /><br />Factoring the quadratic equation, we have:<br /><br />$(x + 4)(x - 3) = 0$<br /><br />Setting each factor equal to zero, we find the possible values of x:<br /><br />$x + 4 = 0$ or $x - 3 = 0$<br /><br />Solving for x, we get:<br /><br />$x = -4$ or $x = 3$<br /><br />Therefore, the possible values of x are -4 and 3.