Find the vertex of the parabola y=x^2 Simplify both coordinates and write them as proper fractions, improper fractions, square square

## Step 1<br />The given equation is \(y = x^2\). This is a quadratic equation in the form \(y = ax^2 + bx + c\), where \(a = 1\), \(b = 0\), and \(c = 0\).<br /><br />## Step 2<br />The vertex of a parabola in the form \(y = ax^2 + bx + c\) is given by the formula \((-b/2a, f(-b/2a))\).<br /><br />## Step 3<br />Substitute the values of \(a\) and \(b\) into the formula to find the x-coordinate of the vertex.<br /><br />### \(x = -b/2a = -0/2*1 = 0\)<br /><br />## Step 4<br />Substitute \(x = 0\) into the equation \(y = x^2\) to find the y-coordinate of the vertex.<br /><br />### \(y = (0)^2 = 0\)