7. Cross a Carrier Female with a Colorblind Male in a Punnett square. a. What is the female's genotype? __ b. What is the male's genotype? __ c. What's the probability their offspring will be colorblind? underline ( )% d. What's the probability of a male child being colorblind? underline ( )% e. What's the probability of a female child being colorblind? underline ( )%

This question is about genetics, specifically about the inheritance of color blindness. Color blindness is a sex-linked recessive trait, which means it is carried on the X chromosome. Females have two X chromosomes, while males have one X and one Y chromosome. <br /><br />a. The female in this question is a carrier, which means she has one normal vision allele (X^N) and one colorblind allele (X^c). So, her genotype is X^NX^c.<br /><br />b. The male in this question is colorblind, which means he has the colorblind allele on his only X chromosome. So, his genotype is X^cY.<br /><br />c. When we cross these genotypes in a Punnett square, we find that there is a 50% chance their offspring will be colorblind. This is because half of the possible combinations (X^cY and X^cX^c) result in colorblindness.<br /><br />d. The probability of a male child being colorblind is 100%, because all possible combinations for male children (X^cY and X^NY) result in colorblindness.<br /><br />e. The probability of a female child being colorblind is 50%, because half of the possible combinations (X^cX^c and X^cX^N) result in colorblindness.