Solve the following observing significant figure rules 8365m/0.006s 1times 10^6m/s 1394166.667m/s 1.394times 10^6m/s 1.39times 10^6m/s

To solve the problem while observing significant figure rules, we need to consider the number of significant figures in each of the given values.<br /><br />The value \(8365 \, \text{m}\) has four significant figures. The value \(0.006 \, \text{s}\) has one significant figure because leading zeros are not counted as significant.<br /><br />When performing division, the result should be reported with the same number of significant figures as the measurement with the fewest significant figures. In this case, that is one significant figure.<br /><br />Now, let's perform the division:<br /><br />\[<br />\frac{8365 \, \text{m}}{0.006 \, \text{s}} = 1394166.667 \, \text{m/s}<br />\]<br /><br />Since we need to round this result to one significant figure, we look at the first digit and the digit immediately following it:<br /><br />- The first digit is 1.<br />- The next digit is 3, which means we do not round up.<br /><br />Therefore, the result rounded to one significant figure is:<br /><br />\[ <br />1 \times 10^{6} \, \text{m/s} <br />\]<br /><br />Thus, the correct answer, considering significant figures, is:<br /><br />\[ <br />1 \times 10^{6} \, \text{m/s} <br />\]