Question 1 (20 points) What are the coefficients for this equation to be properly balanced? underline ( )HCN+underline ( )CuSO_(4)arrow underline ( )H_(2)SO_(4)+underline ( )Cu(CN)_(2) a 1,3,2,1 b 2,1,1,1 C 1,2,2,1 d 2,2,1,2

## Step 1<br />The given chemical equation is \(HCN + CuSO_{4} \rightarrow H_{2}SO_{4} + Cu(CN)_{2}\). To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />## Step 2<br />Looking at the equation, we can see that there is 1 atom of H, 1 atom of C, and 1 atom of N on the left side (in HCN). On the right side, there are 2 atoms of H, 1 atom of C, and 2 atoms of N (in \(H_{2}SO_{4}\) and \(Cu(CN)_{2}\)).<br /><br />## Step 3<br />To balance the H and N atoms, we need to multiply the HCN by 2, which gives us 2 HCN molecules. This results in 2 H atoms and 2 N atoms on the left side.<br /><br />## Step 4<br />Now, the equation looks like this: \(2 HCN + CuSO_{4} \rightarrow H_{2}SO_{4} + Cu(CN)_{2}\).<br /><br />## Step 5<br />Next, we need to balance the Cu and S atoms. There is 1 atom of Cu and 1 atom of S on both sides of the equation, so they are already balanced.<br /><br />## Step 6<br />Finally, we need to balance the O atoms. There are 4 O atoms on the left side (in \(CuSO_{4}\)) and 4 O atoms on the right side (in \(H_{2}SO_{4}\)), so they are also balanced.