Resta. square =8(2)/(8)-3(3)/(8)

To solve the expression \(8\frac{2}{8} - 3\frac{3}{8}\), we first convert the mixed numbers to improper fractions.<br /><br />1. Convert \(8\frac{2}{8}\) to an improper fraction:<br /> \[<br /> 8\frac{2}{8} = 8 + \frac{2}{8} = \frac{8 \times 8 + 2}{8} = \frac{64 + 2}{8} = \frac{66}{8}<br /> \]<br /><br />2. Convert \(3\frac{3}{8}\) to an improper fraction:<br /> \[<br /> 3\frac{3}{8} = 3 + \frac{3}{8} = \frac{3 \times 8 + 3}{8} = \frac{24 + 3}{8} = \frac{27}{8}<br /> \]<br /><br />Now, subtract the two improper fractions:<br />\[<br />\frac{66}{8} - \frac{27}{8} = \frac{66 - 27}{8} = \frac{39}{8}<br />\]<br /><br />Convert the improper fraction back to a mixed number:<br />\[<br />\frac{39}{8} = 4\frac{7}{8}<br />\]<br /><br />So, the final answer is:<br />\[<br />\square = 4\frac{7}{8}<br />\]