__ Prior to 1978, lead (II) chromate powder was often used as an additive to paint mixtures to create a strong yellow color. The most common means to synthesize this powder was by reacting lead (II)oxide ore with chromic acid to produce lead (II) chromate and water. Which equation shows the properly balanced reaction that produces lead (II) chromate and water from the reaction of chromic acid and lead (II) oxide ore? 2Pb_(2)O+H_(2)CrO_(4)arrow Pb_(2)CrO_(4)+H_(2)O PbO_(2)+2HCrO_(4)arrow Pb(CrO_(4))_(2)+2H_(2)O (b) PbO+H_(2)CrO_(4)arrow PbCrO_(4)+H_(2)O 2PbO+HCrO_(4)arrow 2PbCrO_(4)+H_(2)O

To determine the correct balanced chemical equation for the reaction between lead (II) oxide ore and chromic acid to produce lead (II) chromate and water, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Let's analyze each option:<br /><br />1. $2Pb_{2}O+H_{2}CrO_{4}\rightarrow Pb_{2}CrO_{4}+H_{2}O$<br /> - This equation is not balanced correctly. The number of lead atoms is not the same on both sides.<br /><br />2. $PbO_{2}+2HCrO_{4}\rightarrow Pb(CrO_{4})_{2}+2H_{2}O$<br /> - This equation is not balanced correctly. The number of chromium atoms is not the same on both sides.<br /><br />3. $PbO+H_{2}CrO_{4}\rightarrow PbCrO_{4}+H_{2}O$<br /> - This equation is balanced correctly. The number of atoms of each element is the same on both sides.<br /><br />4. $2PbO+HCrO_{4}\rightarrow 2PbCrO_{4}+H_{2}O$<br /> - This equation is not balanced correctly. The number of lead atoms is not the same on both sides.<br /><br />Therefore, the correct balanced chemical equation is:<br />$PbO+H_{2}CrO_{4}\rightarrow PbCrO_{4}+H_{2}O$