4Fe+3O_(2)arrow 2Fe_(2)O_(3) 4. How many grams of Fe_(2)O_(3) are needed to produce 26 moles of Fe? 9anstedue

To determine how many grams of Fe2O3 are needed to produce 26 moles of Fe, we need to use the balanced chemical equation:<br /><br />4Fe + 3O2 → 2Fe2O3<br /><br />From the equation, we can see that 4 moles of Fe are produced for every 2 moles of Fe2O3. Therefore, to produce 26 moles of Fe, we need:<br /><br />26 moles Fe * (2 moles Fe2O3 / 4 moles Fe) = 13 moles Fe2O3<br /><br />Now, we need to convert moles of Fe2O3 to grams. The molar mass of Fe2O3 is:<br /><br />Fe2O3 = (2 * 55.85 g/mol) + (3 * 16.00 g/mol) = 159.69 g/mol<br /><br />So, 13 moles of Fe2O3 is equivalent to:<br /><br />13 moles Fe2O3 * 159.69 g/mol = 2078.37 g Fe2O3<br /><br />Therefore, 2078.37 grams of Fe2O3 are needed to produce 26 moles of Fe.